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思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。。heLLoword翻译官方下载对此有专业解读
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The code runs as a standard Linux process. Seccomp acts as a strict allowlist filter, reducing the set of permitted system calls. However, any allowed syscall still executes directly against the shared host kernel. Once a syscall is permitted, the kernel code processing that request is the exact same code used by the host and every other container. The failure mode here is that a vulnerability in an allowed syscall lets the code compromise the host kernel, bypassing the namespace boundaries.
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